Answer:
Explanation:
use "s" to represent the cost of a small flag and "l" to represent the cost of a large flag. We can set up a system of equations to solve for s and l:
12s + 6l = 432
9s + 3l = 260
We can simplify the second equation by dividing both sides by 3:
3s + l = 86
Now we can use substitution to solve for s. We can isolate l in the second equation:
l = 86 - 3s
Then we can substitute this expression for l into the first equation:
12s + 6(86 - 3s) = 432
Simplifying and solving for s, we get:
12s + 516 - 18s = 432
-6s = -84
s = 14
So the cost of a small flag is 14 AED. We can substitute this value back into the simplified second equation to solve for the cost of a large flag:
3(14) + l = 86
l = 44
Therefore, the cost of a large flag is 44 AED and the cost for the small flag is 14 AED