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Find the x- and y-intercepts of the graph of the linear equation 3x+6y=2

User Pretzelb
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Answer:

x-intercept: 2/3

y-intervept: 1/3

Explanation:

3x + 6y = 2

You're supposed to 'cover them'.

If you want to find the x-intercept, you will cover 6y like it doesn't exist. So now, it's going to be:

3x = 2

You'll then solve for x, which will be the x-intercept

3x/3 = 2/3 (Divide both sides by 3)

x = 2/3 or 0.66... (the 6 goes on forever)

Now, to find y, you'll act like x doesn't exist. It's going to be:

6y = 2

Solve for y, which will be the y-intercept

6y/6 = 2/6 (Divide both sides by 6)

y = 1/3 or 0.33... (the 3 goes on forever)

If you put them as coordinates:

x-intercept: (2/3, 0)

y-intercept: (0, 1/3)

User Kingofmit
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