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the shorter leg of a right triangle is 8 less than the hypotenuse. The longer leg is 1 less than the hypotenuse. Find the perimeter of the triangle

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Answer:

Explanation:

Let's assume that the hypotenuse of the right triangle has a length of x.

According to the problem statement, the shorter leg is 8 less than the hypotenuse, so its length is x - 8.

Similarly, the longer leg is 1 less than the hypotenuse, so its length is x - 1.

We can now use the Pythagorean theorem to write an equation that relates the lengths of the three sides:

(x - 8)^2 + (x - 1)^2 = x^2

Expanding and simplifying this equation, we get:

2x^2 - 18x + 65 = 0

Solving for x using the quadratic formula, we get:

x = (18 ± √244) / 4

We can discard the negative solution, as x represents the length of the hypotenuse, which must be positive. So we have:

x = (18 + √244) / 4 ≈ 6.12

Now we can calculate the lengths of the other two sides:

Shorter leg: x - 8 ≈ -1.88 (discard, as it is negative)

Longer leg: x - 1 ≈ 5.12

The perimeter of the triangle is the sum of the lengths of the three sides:

Perimeter = x + (x - 1) + (x - 8) = 3x - 9

Substituting x ≈ 6.12, we get:

Perimeter ≈ 3(6.12) - 9 ≈ 9.36

Therefore, the perimeter of the right triangle is approximately 9.36.

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