Answer:
Step-by-step explanation:
The number of atoms in 2.418 moles of Bromine can be calculated using Avogadro's constant, which is 6.022 × 10^23 particles per mole.
First, we need to find the total number of Bromine atoms in 2.418 moles:
Number of Bromine atoms = number of moles × Avogadro's constant
Number of Bromine atoms = 2.418 moles × 6.022 × 10^23 atoms/mole
Number of Bromine atoms = 1.455 × 10^24 atoms
Therefore, there are 1.455 × 10^24 atoms in 2.418 moles of Bromine.
To calculate the mass of 8.7 moles of CH4, we need to use the molar mass of CH4, which is the sum of the atomic masses of its elements.
The atomic masses of carbon and hydrogen are 12.01 g/mol and 1.01 g/mol, respectively. The molar mass of CH4 is:
Molar mass of CH4 = (1 × atomic mass of C) + (4 × atomic mass of H)
Molar mass of CH4 = (1 × 12.01 g/mol) + (4 × 1.01 g/mol)
Molar mass of CH4 = 16.05 g/mol
Now we can use this molar mass to find the mass of 8.7 moles of CH4:
Mass of CH4 = number of moles × molar mass
Mass of CH4 = 8.7 moles × 16.05 g/mol
Mass of CH4 = 139.84 g
Therefore, there are 139.84 grams of CH4 in 8.7 moles.