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A group of students at another university conducted a similar density experiment where they found the mean % sugar of triplicate "unknown" trials as 11.98% (sx = 0.98). They identified the "unknown" as Cranberry Juice, since the Nutritional Label lists 12.16% sugar.

Does the % sugar differ significantly (at the 95% confidence level) from the accepted value? Conduct a t-test to find out.

User Antonio
by
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1 Answer

2 votes

Answer:

t-value = 4.30

right side of the inequality: (4.30)(0.98/(s.r)3)

|12.16-11.98| = 0.18 > 2.43

conclusion: The difference is NOT statistically significant since the left side of the inequality is NOT greater than the right side

User Kushan Randima
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9.3k points
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