Question

What is the temperature in K of 16.45 moles of methane gas in a 70.7 L container at 3557 torr

Answer 1

Using the ideal gas law: PV=nRT

P is pressure; V is volume; n is the amount in moles; R=0.082; T is temperature in K.

(4.68)*(4.95)=(16.45)*(0.0821)*T

Solve for T.

T=17.15

Answer 2

Below

Step-by-step explanation:

Ideal gas law :

PV = n R T R = gas constant =62.363598 L torr/((K mole) n = # moles

PV/(nR) = T

3557 torr * 70.7 L / (62.363598 L torr/(K mole) * 16.45 mole) = 245 K