Question

NO LINKS!! URGENT HELP PLEASE!!!

1. When Ronald goes to BIG Burgers, he orders a sandwich and a side order. For the sandwich, 50% of the time he orders a Jumbo Burger, 30% of the time he orders a Chicken Sandwich, and 20% of the time he orders a Regular Burger. For the side, 25% of the time he orders Regular Fries, 40% of the time he orders Curly Fries, and the rest of the time he orders a salad. Ronald just bought lunch. What is the probability that he ordered a Jumbo Burger with Regular Fries or a Chicken Sandwich with a Salad? Make an area and tree diagran to help with the problem.

Answer 1

0.23 or 23%.

Explanation:

To solve this problem, we need to find the probability of two specific combinations: Jumbo Burger with Regular Fries, and Chicken Sandwich with a Salad. We can use an area diagram and a tree diagram to help us visualize the probabilities.

Area Diagram: Attachment

Using the area diagram or the tree diagram, we can see that there are four possible outcomes that meet the criteria: Jumbo Burger with Regular Fries, Jumbo Burger with Curly Fries, Chicken Sandwich with a Salad, and Regular Burger with Regular Fries. We can find the probabilities of these outcomes by multiplying the probabilities of the sandwich and side orders.

Probability of Jumbo Burger with Regular Fries: 0.5 x 0.25 = 0.125

Probability of Jumbo Burger with Curly Fries: 0.5 x 0.4 = 0.2

Probability of Chicken Sandwich with a Salad: 0.3 x 0.35 = 0.105

Probability of Regular Burger with Regular Fries: 0.2 x 0.25 = 0.05

To find the probability of Ronald ordering a Jumbo Burger with Regular Fries or a Chicken Sandwich with a Salad, we need to add the probabilities of these two outcomes:

0.125 + 0.105 = 0.23 or 23%

Therefore, the probability that Ronald ordered a Jumbo Burger with Regular Fries, or a Chicken Sandwich with a Salad is 0.23 or 23%.

Answer 2

The probability that Ronald ordered a Jumbo Burger with Regular Fries OR a Chicken Sandwich with a Salad is 23%.

Explanation:

A tree diagram shows the probabilities for a sequence of two or more independent events.

For the given problem:

• The first event is the choice of sandwich.
• The second event is the choice of side order.

Given probabilities for each event:

• Jumbo burger = 50%
• Chicken sandwich = 30%
• Regular burger = 20%
• Regular fries = 25%
• Curly fries = 40%
• Salad = 100% - 25% - 40% = 35%

Create a tree diagram with the given information (see attachment 1).

The end of each branch should be labelled with its outcome, and the probability of that event should be written along the branch.

To calculate the probability of each combination, multiply the probabilities along the branches.

To find the probability that Ronald ordered a Jumbo Burger with Regular Fries, multiply along the branches representing those events:

⇒ 50% × 25% = 12.5%

To find the probability that Ronald ordered a Chicken Sandwich with a Salad, multiply along the branches representing those events:

⇒ 30% × 35% = 10.5%

On a tree diagram, when moving along the branches (from left to right) we multiply, and when moving down we add.

Therefore, to calculate the probability that Ronald ordered a Jumbo Burger with Regular Fries OR a Chicken Sandwich with a Salad, add the two found probabilities:

⇒ 12.5% + 10.5% =23%