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Find a function of the form y = A sin B(x - C) with the given properties. Amplitude: 2/3; Period: pi/4; Phase Shift: pi/6 units to the left

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Answer:

Explanation:

The general form of a sinusoidal function is given by:

y = A sin (Bx - C) + D

where A is the amplitude, B is the frequency, C is the phase shift, and D is the vertical shift.

Given: Amplitude = 2/3, Period = pi/4, Phase Shift = pi/6 units to the left

The amplitude is 2/3, which means that A = 2/3.

The period is pi/4, which means that one cycle of the function occurs over a distance of pi/4. We know that the period is related to the frequency by the formula:

Period = 2pi / B

Solving for B, we get:

B = 2pi / Period

B = 2pi / (pi/4)

B = 8

The phase shift is pi/6 units to the left, which means that C = pi/6.

Finally, there is no vertical shift in this case, so D = 0.

Putting it all together, we get:

y = (2/3) sin (8x - pi/6)

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