Question

What is the expression, 2x^2+5y-8 when x=5 and y=-2?​

Answer 1

Explanation:

Substitute x=5 and y=-2 in the expression:

2x^2+5y-8 = 2(5)^2 + 5(-2) - 8

= 2(25) - 10 - 8

= 50 - 18

= 32

Therefore, the value of the expression 2x^2+5y-8 when x=5 and y=-2 is 32.

Answer 2

Answer: C) 32

Explanation:

The exercise is 2x² + 5y - 8

Here we substitute in the exercise x and y.

• x = 5
• y = -2

We follow the PEMDAS order of operations:

• P - Patents
• E - Exponents
• M - Multiplication
• D-Division
• A - Addition
• S - Subtraction

We substitute and solve:

2(5)² + 5(-2) - 8

2(25) + 5(-2) - 8

50 + 5(-2) - 8

50 - 10 - 3

32 ===> Alternative C