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Line m passes through the points (6, 10 and (4, 6). Which equation represents a line that perpendicular to line m​

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Answer:

y - 6 = (-1/2)(x - 4)

Step-by-step explanation:

As we go from (4, 6) to (6, 10), x (the run) increases by 2 and y (the rise) increases by 4. Thus, the slope of the line connecting these two points is m = rise / run = 4/2 = 2.

The slope of a line perpendicular to this one is the negative reciprocal of 2, which is -1/2.

Using the point-slope formula, we get the following equation for the perpendicular line:

y - 6 = (-1/2)(x - 4) ( obtained using the point (4, 6) )

User Skarist
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11 votes

Final answer:

The equation of a line perpendicular to line m can be written as y = (-1/2)x + b, where b is a constant.

The answer is option ⇒1

Step-by-step explanation:

To find a line that is perpendicular to line m, we need to determine the slope of line m and then find the negative reciprocal of that slope.

The slope of a line passing through two points (x₁, y₁) and (x₂, y₂) can be calculated using the formula:

slope = (y₂ - y₁) / (x₂ - x₁)

Given the points (6, 10) and (4, 6), we can calculate the slope of line m:

slope = (6 - 10) / (4 - 6)

= -4 / -2

= 2

To find a line perpendicular to line m, we need to find the negative reciprocal of the slope. The negative reciprocal of 2 is -1/2.

Therefore, the equation of a line that is perpendicular to line m can be written in the form y = (-1/2)x + b, where b is the y-intercept.

Since we don't have enough information to determine the y-intercept, we cannot provide a specific equation that represents a line perpendicular to line m. However, any equation in the form y = (-1/2)x + b, where b is a constant, represents a line that is perpendicular to line m.

To summarize:

- The slope of line m is 2.

- The equation of a line perpendicular to line m can be written as y = (-1/2)x + b, where b is a constant.

The answer is option ⇒1

Your question is incomplete, but most probably the full question was:

Line m passes through the points (6, 10 and (4, 6). Which equation represents a line that perpendicular to line m​

y = (-1/2)x + b

y = 2x + b

y = -1/2x + b

y =-2x + b

User SANAT
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