Question

A man pushes a lawn mower on a level lawn with a force of 186 N. If 26% of the force is directed horizontally, how much work is done by the man in pushing the mower 6.5 m?

Answer 1

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Step-by-step explanation:

Answer 2

W = 48.36 x 6.5 = 314.34 J.

Step-by-step explanation:

The work done by the man in pushing the mower is the force multiplied by the displacement. Since 26% of the force is directed horizontally, we can calculate the amount of force that is directed horizontally as 0.26 x 186 N = 48.36 N. The work done is then calculated as W = F x s, where F is the horizontal force and s is the displacement. Therefore, the work done by the man in pushing the mower 6.5 m is W = 48.36 x 6.5 = 314.34 J.