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A 2.25−L vessel contains 4.70 g of a gas at 1.00 atm and 27.0°C. (a) Calculate the density of the gas in g/L.

User Latishia
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ANSWER-

To calculate the density of the gas in g/L, we need to use the ideal gas law equation:

PV = nRT

where P is the pressure of the gas, V is the volume of the container, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15 K to the Celsius temperature:

T = 27.0°C + 273.15 = 300.15 K

Next, we can solve for the number of moles of gas:

n = (molecular weight of gas * mass of gas) / (molar mass constant * temperature)

where the molecular weight of the gas is needed to be known. Let's assume the gas is an ideal gas, so we can use the molar mass of the gas as its molecular weight. Without knowing the identity of the gas, we cannot determine its molar mass, but we can use the general gas law to solve for density.

From the ideal gas law equation, we can rearrange to solve for n/V, which is the density of the gas in g/L:

n/V = P/RT

where P is the pressure of the gas in atm, R is the ideal gas constant (0.08206 Latm/(molK)), and T is the temperature of the gas in Kelvin.

Substituting the given values:

n/V = (1.00 atm) / (0.08206 Latm/(molK) * 300.15 K) = 0.0401 mol/L

We can use the molar mass of the gas to convert from moles per liter to grams per liter:

density = (mass of gas) / (volume of container)

density = (4.70 g) / (2.25 L) = 2.09 g/L

Therefore, the density of the gas in the container is 2.09 g/L.
User Yam Mesicka
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