Question

What is the molarity of solution if 42.1 grams of KOH is dissolved in 3.0 L of solution?

Answer 1

Answer: 9.23 moles of solute

Explanation: It's a hard explanation so you can just have the answer.

Answer 2

the molarity of the solution is 0.25 M.

Step-by-step explanation:

To calculate the molarity of a solution, we need to know the amount of solute in moles and the volume of the solution in liters.

The first step is to calculate the amount of KOH in moles using its molar mass. The molar mass of KOH is the sum of the atomic weights of potassium (39.1 g/mol), oxygen (16.0 g/mol), and hydrogen (1.0 g/mol):

Molar mass of KOH = 39.1 g/mol + 16.0 g/mol + 1.0 g/mol = 56.1 g/mol

The amount of KOH in moles is:

moles of KOH = mass of KOH / molar mass of KOH

moles of KOH = 42.1 g / 56.1 g/mol

moles of KOH = 0.750 moles

Now that we know the amount of KOH in moles, we can calculate the molarity of the solution:

Molarity = moles of solute / liters of solution

Molarity = 0.750 moles / 3.0 L

Molarity = 0.25 M

Therefore, the molarity of the solution is 0.25 M.