Question

Gena's age is twice of her sister Emily's age. Before 10 years, she was twelve times as old as her sister. What is the sum of the present age of Gena and her sister together?

Answer 1

Explanation:

Let's assume Emily's present age to be x.

According to the problem, Gena's age is twice Emily's age, which means that Gena's present age is 2x.

The problem also states that 10 years ago, Gena was twelve times as old as Emily. So, we can set up an equation based on this information:

2x - 10 = 12(x - 10)

Simplifying this equation, we get:

2x - 10 = 12x - 120

Subtracting 2x from both sides, we get:

-10 = 10x - 120

Adding 120 to both sides, we get:

110 = 10x

Dividing both sides by 10, we get:

x = 11

Therefore, Emily's present age is 11, and Gena's present age is 2x = 22. The sum of their ages is:

11 + 22 = 33

So, the sum of the present age of Gena and Emily is 33.