Question

How do you find the square root of 27 over m to the fifth power

Answer 1

- 17 - 27 - 27 - 27 - 37 five times 27:37

Answer 2

To find the square root of 27 over m to the fifth power, we can break it down into two separate parts: the square root of 27 and the square root of m to the fifth power.

First, we can simplify the square root of 27 to get √27 = √(9 x 3) = √9 x √3 = 3√3.

Next, we can simplify the square root of m to the fifth power to get (√m)^5 = m^(5/2).

Putting it all together, we get:

√(27/m^5) = √27/√m^5 = 3√3/m^(5/2)

Therefore, the square root of 27 over m to the fifth power is 3√3/m^(5/2).