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Mrs. Parker is a librarian at Eastside Library. In examining a random sample of the library's book collection, she found the following.
753 books had no damage, 74 books had minor damage, and
30 books had major damage.
Based on this sample, how many of the 76,500 books in the collection should Mrs. Parker expect to have minor damage or major damage? Round your answer
to the nearest whole number. Do not round any Intermediate calculations

2 Answers

4 votes

Answer:

Mrs. Parker should expect around 9284 books in the library's collection to have minor damage or major damage.

Explanation:

To calculate the expected number of books with minor or major damage in the entire collection, we can scale up the sample proportion to the size of the full collection.

First, let's find the proportion of books with minor or major damage in the sample:

Proportion = (74 + 30) / (753 + 74 + 30) = 104 / 857 = 0.1214

Next, we'll scale up this proportion to the size of the full collection:

expected number of books with minor or major damage = proportion * 76,500 = 0.1214 * 76,500 = 9283.5472578763

Finally, we round the result to the nearest whole number:

expected number of books with minor or major damage = round(9283.5472578763 ) = 9284

So, Mrs. Parker should expect around 9284 books in the library's collection to have minor damage or major damage.

User Vadzim
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6 votes

Answer: Around 9,284 books.

Explanation:

First, we will find how large this sample is by using addition.

753 + 74 + 30 = 857

Next, since we are looking for the expected minor or major damage, we will find the number of books from this sample that meet the requirements.

74 + 30 = 104

Now, we will find the percentage of this sample that meets the criteria.

(104 / 857) * 100 ≈ 12.13536%

Lastly, we will use this value to determine how many books in the collection are likely to have minor or major damage.

76,500 * 12.13536% = 9,283.55 ≈ 9,284 books

User Demarsch
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