Question

2. I am a regular polygon. One of my interior angles is 135°. What size is one of

my exterior angles?

Answer 1

Answer: The sum of the interior angles of a regular polygon can be found using the formula:

(n-2)180°, where n is the number of sides of the polygon.

Let's call the number of sides of the polygon "s".

We know that one of the interior angles is 135°, so we can set up an equation using the formula for the sum of the interior angles:

s * 135° = (s-2)180°

Expanding the right side of the equation:

s * 135° = (s-2) * 180°

s * 135° = s * 180° - 360°

Solving for s:

135° = 180° - 360°/s

135° = 180° - 2 * 180°/s

135° = 180° - 2 * (180°/s)

180° - 135° = 2 * (180°/s)

45° = (180°/s)

So, s = 180° / 45° = 4 sides.

The size of one exterior angle can be found by subtracting each interior angle from 360°:

360° - 135° = 225°.

Therefore, one exterior angle of the polygon is 225°.

Explanation:

Answer 2

45°

Explanation:

Given a polygon with an interior angle of 135°, you want to know the measure of the corresponding exterior angle.

Exterior angle

At any given vertex of a polygon, the interior and exterior angles are supplementary:

exterior angle = 180° - interior angle

exterior angle = 180° -135°

exterior angle = 45°