Question

jane sat in a chair and exercised a knee extension. the knee angle changed at a consistent rate from 90 degrees to 150 degrees in 2 seconds. shank length was 0.4 m. calculate (a) angular displacement of the knee, (b) angular velocity of the knee, (c) angular acceleration of the knee, (d) angular distance of the foot, (e)

Answer 1

Step-by-step explanation:

Angular velocity is measured in angle per unit time or radians per second (rad/s). The rate of change of angular displacement is angular velocity.

Displacement in such motion is in the form of angle and hence known as angular displacement.

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\theta = wt + 1/2 \alpha t^{2}

\theta the angular displacement of the object

s distance covered by the object on the circular path

r the radius of curvature of the given path

\omega initial angular velocity

t time