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Two sides of a triangle are

shown. Find the range of
values of the third side.
10, 5
< X

Two sides of a triangle are shown. Find the range of values of the third side. 10, 5 &lt-example-1

1 Answer

4 votes

Answer:

5 < x < 15

Explanation:

The triangle inequality theorem states that the sum of the measures of any two sides of a triangle must be greater than the measure of the third side

In the given triangle we are provided measures of two of the sides as 10 and 5

Let the measure of the third side be x

So the three sides are 10, 5 and x

Then by the inequality theorem
10 + 5 > x

==> 15 > x or

x < 15 This is an upper bound for x

when we switch sides in an inequality > changes to < and < changes to >

We also have
x + 5 > 10 ==> x > 10 - 5 ==> x > 5

and

x + 10 > 5 ==> x > -5

Since x > 5 is more restrictive than x > -5, we conclude that x > 5 or 5 < x is the lower bound on x

Combining all inequalities we get

5 < x < 15

Note

We could also state the lower and upper bound limits as

difference of two sides < x < sum of two sides
10 - 5 < x < 10 + 5

or

5 < x < 15

While this may seem easier to compute than the explanation given above, the derivation is left out and may confuse some students

User Lahib
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