Question

A BOULDER (m=120kg) SITTING ON A 4 -m TALL CLIFF FALLS DOWN SUDDENLY . WHAT IS THE BOULDER'S KINETIC ENERGY (IN J) RIGHT BEFORE HITTING THE GROUND?

Answer 1

4704 J

Step-by-step explanation:

All of the GPE the boulder had at the top of the cliff converts to KE, therefore:

KE = GPE = mgh = (120 kg)(9.8 m/s²)(4 m) = 4704 J

Answer 2

Don't understand sorry