Question

A gas occupies a volume of 43.6 mL at STP. Calculate the temperature that the gas will be if the volume is changed to 50.0mL and pressure is reduced to 98.0kPa.

Answer 1

302.8K

Step-by-step explanation:

Using the combined gas equation:

V1P1/T1 = V2P2/T2

V1 = 43.6mL

P1 = Standard Pressure = 101.325kPa

T1 = Standard Temperature = 273K

V2 = 50.0mL

P2 = 98.0kPa

T2 = ?

T2 = V2P2T1/V1P1

T2 = 50×98×273 / 43.6×101.325

T2 = 302.8K