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User PacketLoss
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1 Answer

5 votes

Answer:

Explanation:

First Image:


cos49=(14)/(x)\\


x=(14)/(cos49) =(14)/(0.656) =21.34 =21

Second Image


tan52=(x)/(20) \\x=20*tan52\\x=20*1.28=25.59\\x=26

Third Image


cos15=(x)/(33)\\x=33*cos15\\x=33*0.966\\x=31.87\\x=32

Fourth Image


cos16=(x)/(37)\\x=37*cos16\\x=37*0.96\\x=35.56\\x=35

Fifth Image


tan51 =JL/14\\

First, we must calculate the length of JL, the common side of both triangles before calculating KL

So;


JL=14*tan51\\JL=14*1.23=17.28\\JL=17\\\\Knowing JL now we can calculate KL\\\\Cos72=(KL)/(JL)\\\\Isolating KL\\\\KL=JL*cos72\\KL=17*cos72 = 17*0.31=5.25\\KL=5

User Seif Tml
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