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Find the area of a triangle with a =17, b =13, and c =19.

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Answer -

The area of a triangle can be found using Heron's formula, which states that the area of a triangle with sides a, b, and c is:

Area = √(s(s-a)(s-b)(s-c))
where s is the semi-perimeter of the triangle, defined as s = (a + b + c) / 2.

So, for a triangle with sides a = 17, b = 13, and c = 19:

s = (17 + 13 + 19) / 2 = 49 / 2 = 24.5
Area = √(24.5(24.5-17)(24.5-13)(24.5-19))
Area = √(24.5 * 7.5 * 11.5 * 5.5)
Area = √(10912.5)
Area = 104.72

The area of the triangle is approximately 104.72 square units.
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