Answer:
don't worry, you'll live.
Explanation:
The figure with the vertices G(-4,1), H(4,1) and I(0,-2) is an isosceles triangle , the perimeter is 18 cm and the area is 12cm² .
In the question ,
it is given that
On plotting the vertices , we can see that the vertices form a triangle .
the graph is shown below.
to find the the Perimeter and Area we need length of triangle ,
given vertices G(-4, 1), H(4, 1), I(0, -2)
So ,
length of GH=√(4-(-4))²+(1-1)² = √8² = 8
length of HI = √(0-4)²+(-2-1)² = √16+9 = √25 = 5
length of GI = √(0-(-4))²+(-2-1)² = √16+9 = √25 = 5
As we can see that two sides of the triangle are equal , hence the figure is an isosceles triangle .
The Perimeter of the triangle GHI = GH+HI+GI
= 8+5+5
= 18 cm
For Area we need the height of the triangle
A is the mid point of GH so , GA = AH = 4
We calculate height(IA)=h using the Pythagoras Theorem in ΔHAI
IH²=IA²+AH²
substituting the values , we get
5²=h²+4²
25 = h² + 16
h² = 25-16
h² = 9
h = 3
hence the height of the triangle is 3 cm
Area of triangle GHI = (1/2)×Base×Height
= (1/2)×8×3
= 12
hence the area is 12 cm².
The figure with the vertices G(-4,1), H(4,1) and I(0,-2) is an isosceles triangle , the perimeter is 18 cm and the area is 12cm² .
The given question is incomplete , the complete question is
Identify the figure with the given vertices. Find the perimeter and area of the figure.
G(-4, 1), H(4, 1), I(0, -2).