Question

The relationship between the intensity of sound((w)/(m^(2)))and the distance from the source of sound is represented by the equation (i)=((k)/(d^(2))).If you sit only one meter away from the stage at a rock concert the intensity of sound is about 0.1(w)/(m^(2)). If vanessa does not want the sound intensity to be more than 0.001(w)/(m^(2)) how close to the stage can she sit?

Answer 1

10 m

Explanation:

We are given that the relationship between intensity of sound and distance from the source is given by

Intensity (I)=
`(k)/(d^2)`

Where I=Intensity

d=Distance of sound from the source

If distance d=1m

Intensity, I=0.1
`w/m^2`

We have to find how close she can to the stage if vanessa does not want the sound intensity to be more than 0.001(w)/(m^(2)).

Using the formula

`0.1=(k)/(1)`

`k=0.1`

`(0.1)/(d^2)\leq 0.001`

`(0.1)/(0.001d^2)\leq 1`

`(0.1)/(0.001)\leq d^2`

`100\leq d^2`

`10\leq d`

`d=10 m`

Hence, she can sit 10 m away from the stage.