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The relationship between the intensity of sound((w)/(m^(2)))and the distance from the source of sound is represented by the equation (i)=((k)/(d^(2))).If you sit only one meter away from the stage at a rock concert the intensity of sound is about 0.1(w)/(m^(2)). If vanessa does not want the sound intensity to be more than 0.001(w)/(m^(2)) how close to the stage can she sit?

User Mr Pang
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1 Answer

4 votes

Answer:

10 m

Explanation:

We are given that the relationship between intensity of sound and distance from the source is given by

Intensity (I)=
(k)/(d^2)

Where I=Intensity

d=Distance of sound from the source

If distance d=1m

Intensity, I=0.1
w/m^2

We have to find how close she can to the stage if vanessa does not want the sound intensity to be more than 0.001(w)/(m^(2)).

Using the formula


0.1=(k)/(1)


k=0.1


(0.1)/(d^2)\leq 0.001


(0.1)/(0.001d^2)\leq 1


(0.1)/(0.001)\leq d^2


100\leq d^2


10\leq d


d=10 m

Hence, she can sit 10 m away from the stage.

User Woland
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