89.6k views
3 votes
Cards labeled 5, 6, 7, 8, and 9 are in a stack. A card is drawn and not replaced. Then, a second card is drawn at random. Find the probability of drawing an even number first, then an odd number second.

User Rockeem
by
8.0k points

2 Answers

5 votes

Answer:

3/10

Explanation:

User Alois Klink
by
9.2k points
4 votes

Answer: 3/10

Work Shown:

A = first card is even

B = second card is odd

P(A) = 2/5 since there are two even cards out of five total

P(B given A) = 3/4 because we have 3 odd cards out of 5-1 = 4 left over total; this is when the first card is not replaced or put back.

P(A and B) = P(A)*P(B given A)

P(A and B) = (2/5)*(3/4)

P(A and B) = (2*3)/(5*4)

P(A and B) = (2*3)/(5*2*2)

P(A and B) = (3)/(5*2)

P(A and B) = 3/10

User Akash Babu
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories