Question

For the reaction represented by the equation 2HNO3 + Mg(OH)2 --> Mg(NO3)2 + 2H2O, how many moles of magnesium nitrate, Mg(NO3)2, are produced from 23.85 grams of nitric acid, HNO3 ?

Answer 1

Expert Verified Answer

Step-by-step explanation:

We can start by converting the amount of nitric acid to moles and then use the balanced chemical equation to find the corresponding amount of magnesium nitrate produced.

First, we convert the amount of nitric acid to moles:

23.85 g HNO3 / 63.01 g/mol = 0.38 moles HNO3

Next, we use the balanced chemical equation to find the corresponding amount of magnesium nitrate produced:

2 moles HNO3 reacts with 1 mole Mg(OH)2 to produce 2 moles Mg(NO3)2

Therefore, 0.38 moles HNO3 would produce 0.38 moles / 2 moles HNO3 = 0.19 moles Mg(NO3)2.