Answer:
Explanation:
Here, ABCD is a parallelogram.
∠CBD=40
o
and ∠BAD=80
o
.
AD∥BC and BD is a transversal.
∴ ∠ADB=∠CBD [ Alternate angles ]
∴ ∠ADB=40
o
.
∴ y=40
o
.
In △ADB,
⇒ ∠ADB+∠DBA+∠BAD=180
o
⇒ 40
o
+x+80
o
=180
o
⇒ 120
o
+x=180
o
⇒ x=180
o
−120
o
⇒ x=60
o
We get, x=60
o
and y=40
o
.