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PLS HELP 50 POINTS

In the figure shown, which pair of angles must be complementary?

A. ∠AXD and ∠DXC

B. ∠AXY and ∠YXB

C. ∠DXC and ∠BXC

D. ∠AXB and ∠BXC

PLS HELP 50 POINTS In the figure shown, which pair of angles must be complementary-example-1
User Masao Liu
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2 Answers

15 votes
15 votes

What can you see in image?

  • A co-ordinate plane
  • AC a straight line

This is enough to find ans

Now

  • <axb and <axc are linear pairs so their sum is 180°

One angle is 90° so other must be 90

  • Complementary angles are of 90°

Hence.

  • <axd and <dxc are complementary
User HSchmale
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13 votes
13 votes

Answer:


B. \text{ } \angle AXY \text{ and } \angle YXB

Skills needed: Angle Geometry

Explanation:

1) We are given a diagram and are asked about complementary angles.

We must fully understand this term prior to solving this problem.

---> Complementary angles are angles that add up to a measure of 90 degrees. Essentially, two complementary angles make up a right angle.

2) Let's find all right angles in the diagram.

-->
\angle BXC is the only marked right angle, but there are 3 others.


\angle {BXD} is a straight angle, since
\overline{BD} is a straight line.

---> A straight angle has a measure of
180\textdegree.


\angle BXC + \angle CXD = \angle BXD as seen in the diagram.

Given
\angle BXC is 90 degrees (since it's a right angle), and
\angle{BXD} is 180 degrees (since it's a straight angle), we can solve for
\angle{CXD}


90+ \angle CXD =180 \\ \angle CXD=90

This means ANGLE CXD is a right angle.

We can do this process 2 more times. Using the fact that
\overline{CA} is a straight line (so
\angle CXA = 180\textdegree), we can determine that
\angle{BXA} and
\angle{DXA} are both right angles.

3) Now let's see if there are any two angles that combine to make a right angle.


\angle{BXC}, \angle{DXC}, \text{ and } \angle{DXA} all are not split.


\angle{BXA} however, is split into two angles (
\angle{YXB}\text{ and } \angle AXY

These two angles would be complementary as they make up a right angle.
B is the answer.

User Pckill
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