Answer:
70.1 liters
Step-by-step explanation:
At Standard Temperature and Pressure (STP), the conditions are defined as a temperature of 0°C (273.15 K) and a pressure of 1 atm. To calculate the volume that 3.20 moles of oxygen gas would occupy at STP, we can use the Ideal Gas Law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Substituting the known values:
P = 1 atm
n = 3.20 moles
R = 0.0821 L·atm/mol·K
T = 273.15 K
Solving for V:
V = (nRT) / P = (3.20 moles * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm = 70.1 liters
In conclusion, 3.20 moles of oxygen gas would occupy 70.1 liters at STP.