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How many moles are present in 152 grams of FeSO4

1 Answer

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Answer:

1.00 moles

Step-by-step explanation:

Find the molar mass of FeSO4. Add the atomic masses (AMU) of each atom present from the periodic table..

1 Fe = 55.84

1 S = 32.1

4 O = 64

============

Total = 151.9 AMU for FeSO4

This is also the same number for the molar mass of FeSO4, but just expressed as grams/mole. It takes 151.9 grams of FeSO4 to have 1 mole of FeSO4 molecules.

The problem states that 152 grams are present. To obtain moles FeSO4, divide by the molar mass:

(152 grams FeSO4)/(151.9 grams/mole FeSO4) = 1.00 moles of FeSO4

[Note that the grams cancel and moles moves to the top in the division]

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