Question

The complex ion Cu(NH3)42+ is formed in a solution made of 0.0200 M Cu(NO3)2 and 0.300 M NH3. What are the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium? The formation constant*, Kf, of Cu(NH3)42+ is 1.70 × 1013.

Answer 1

To determine the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium, we can use the formation constant and stoichiometry of the reaction.

Step-by-step explanation:

The concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium can be determined using the formation constant and the stoichiometry of the reaction. The formation constant, Kf, for Cu(NH3)42+ is 1.70 × 10^13. Assuming that x << 0.0846, which allows us to remove x from the sum and difference, we can calculate the equilibrium concentration of Cu2+. Using the given concentrations of Cu(NO3)2 and NH3, we can determine the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium.