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1.) A husband 3 years older than his wife. The Sum of their ages is 73 years. Calculate the difference between the square of their ages.​

User Kknd
by
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2 Answers

4 votes

Answer:

219

Explanation:

H-W=3

H+W =73

2H=76

H=38

W=35

38² -35² = 219

User Alnafie
by
7.6k points
3 votes

Answer:

  • The difference between the square of their ages is 219

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Let the husband's age be h and wife's age be w.

The difference of their age is 3 and sum is 73:

  • h - w = 3
  • h + w = 73

The difference between the squares is:

  • h² - w² = Difference of squares
  • (h + w)(h - w) = Identity for difference of squares
  • 73*3 = Substitute
  • 219 Answer