a)
Given
perimeter of the rectangle :36
case 1
given length :9
perimeter =2(l+w) l= length,w =width
36 = 2(9+w)
36 = 18+2w
36 -18 =2w
w = 9
area = length * width
= 9*9
= 81 m^2.
case 2
given length :10
perimeter =2(l+w) l= length,w =width
36 = 2(10+w)
36 = 20+2w
36 -20 =2w
w = 8
area = length * width
= 10*8
= 80m^2.
case 3
given length :11
perimeter =2(l+w) l= length,w =width
36 = 2(11+w)
36 = 22+2w
36 -22 =2w
w = 14
area = length * width
= 11*14
= 154 m^2.
b)
he mostly get high yields at field 3 .