Question

Write the equation of the line with slope = 4/6 and passing through the point (1, -1)

Answer 1

Y--1=m(x-1) this is the rule of the equation of straight line

Answer 2

Explanation:

The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept (the point where the line crosses the y-axis).

Given that the slope of the line is m = 4/6, we can substitute it into the equation.

We know that the line passes through the point (1, -1), so we can use that point to find the value of b.

Plugging in the point (1, -1) into the equation, we get:

-1 = (4/6)(1) + b

Solving for b, we get:

b = -1 - (4/6) = -1 - 2/3 = -5/3

So the equation of the line is:

y = (4/6)x - (5/3)

which can be rewritten as

y = (2/3)x - (5/3)

this line is the equation of the line you are looking for.