Question

For events A, B, and C we have that

P(A)=0.24,
P(B)=0.26,
P(A n B)=0.05,
P(A n C)=0.05,
P(B n C)=0.05,
P(A n B n C)=0.02 and P((A u B uC)^/)=0.33,
find P(C)

How should i go about this??

Answer 1

Answer: 0.30

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Work Shown:

P( (A u B u C)' ) = 0.33

P(A u B u C) = 1 - P( (A u B u C)' )

P(A u B u C) = 1 - 0.33

P(A u B u C) = 0.67

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P(AuBuC) = P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

0.67 = 0.24 + 0.26 + P(C) - 0.05 - 0.05 - 0.05 + 0.02

0.67 = P(C) + 0.37

P(C) = 0.67 - 0.37

P(C) = 0.30

For more information, search out "inclusion-exclusion principle". Also feel free to ask me if you have any questions.