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Show that the derivative of f(x) = x^n + x^(n-1) is f'(x) = (nx + n - 1) / x^(2-n)

User Bwdm
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We can use the power rule to find the derivative of f(x) = x^n + x^(n-1). The power rule states that the derivative of x^n is nx^(n-1).

So, the derivative of x^n is nx^(n-1)

And the derivative of x^(n-1) is (n-1)x^(n-2)

So the derivative of f(x) = x^n + x^(n-1) is:

f'(x) = nx^(n-1) + (n-1)x^(n-2)

Now, if we combine the exponents we have :

f'(x) = nx^n-1 + nx^n-2

And we can factor out x^n-2 from the second term, we have:

f'(x) = nx^n-1 + (n-1)x^n-2*x^2

Now, we can simplify the expression by canceling the x^n-2 factor.

f'(x) = nx^n-1 + (n-1)x

And finally, by simplifying the exponent and factoring the constants, we have:

f'(x) = (nx + n - 1) / x^(2-n)

So the derivative of f(x) = x^n + x^(n-1) is f'(x) = (nx + n - 1) / x^(2-n)

User MNM
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