Question

Talia travelled part of the journey by train and the rest by bus. The total fare was sh 4000.On return,the fare of the bus was hiked by a half of what he paid and the total fare of the return journey hiked to sh 4800.Find the train fare.

Answer 1

Answer: Let "t" be the fare of the train.

The fare of the bus is "b".

We know that t + b = 4000 (the total fare of the journey)

On the return trip, the fare of the bus was hiked by half of what was paid, so b*1.5 = b + (b/2) = new fare of the bus.

The total fare of the return journey is 4800, so t + (b + (b/2)) = 4800

Now we have two equations:

t + b = 4000

t + b + (b/2) = 4800

We can substitute the first equation into the second equation:

t + b + (b/2) = 4800

t + (4000 - t) + (b/2) = 4800

t + (b/2) = 800

t = 800 - (b/2)

Now we have an equation that only involves one variable "t" (the fare of the train)

We can substitute the first equation back in:

t + b = 4000

800 - (b/2) + b = 4000

800 = (3/2)b

b = 1200

So the fare of the bus is 1200 and the fare of the train is 800

Explanation: