Question

I need help with this solving system by elimination

Answer 1

x = -6

y = 0

Explanation:

For the first equation, x - 4y = -6, we can move -4y to isolate x. Then, the equation will be: x = -6 + 4y. Now, we can use that x to solve for the second equation, 2x - 12y = -12. Let's plug in x from the first equation down to the second one:

2(-6 + 4y) - 12y = -12

Let's solve:

-12 + 8y - 12y = -12

-4y = 0

y = 0

Now that we have y, we can solve for x. Let's plug in y = 0 for the first problem: x-4(0) = -6

x = -6

Answer 2

(- 6, 0 )

Explanation:

x - 4y = - 6 → (1)

2x - 12y = - 12 → (2)

multiplying (1) by - 2 and adding to (2) will eliminate x

- 2x + 8y = 12 → (3)

add (2) and (3) term by term to eliminate x

(2x - 2x) + (- 12y + 8y) = - 12 + 12

0 - 4y = 0

- 4y = 0 , then

y = 0

substitute y = 0 into either of the 2 equations and solve for x

substituting into (1)

x - 4(0) = - 6

x - 0 = - 6

x = - 6

solution is (- 6, 0 )