Question

The sum of 9 consecutive positive integers is 99. What is the largest of these Intigers?

Answer 1

Answer: 15

Explanation:

Let x be the first of the consecutive integers.

So, the consecutive integer after x would be x+1. The one after this one would be x+2. Continue this until there are nine consecutive integers.

x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) + (x+7) + (x+8) = 99

Simplify:

9x + 36 = 99

9x = 63

x = 7

The largest of these consecutive integers is the last one, x+8. Plug in x to this expression:

(7) + 8 = 15

The largest of these consecutive integers is 15.