Answer: 15
Explanation:
Let x be the first of the consecutive integers.
So, the consecutive integer after x would be x+1. The one after this one would be x+2. Continue this until there are nine consecutive integers.
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) + (x+7) + (x+8) = 99
Simplify:
9x + 36 = 99
9x = 63
x = 7
The largest of these consecutive integers is the last one, x+8. Plug in x to this expression:
(7) + 8 = 15
The largest of these consecutive integers is 15.