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The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

User Rftr
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1 Answer

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Explanation:

The area of a rectangular room is given by the formula A = l * w, where l is the length and w is the width. In this case, we know that A = 750 square feet and w = l - 5 feet. We can use this information to create equations to solve for the length of the room.

Three options that can be used to solve for y are:

y(y + 5) = 750

This equation can be obtained by substituting the given information into the formula for the area of a rectangular room.

y(l - 5) = 750

y(l) - 5y = 750

y2 – 5y = 750

This equation can be obtained by expanding the first equation and moving all the terms to one side of the equation.

y(l) - 5y = 750

y2 - 5y = 750

(y + 25)(y - 30) = 0

This equation can be obtained by factoring the second equation, in which you get two solutions, y = -25 and y = 30. The first solution is not a valid solution because the length of a room can not be negative but the second one is a valid solution.

Note that 750 - y(y - 5) = 0 and y(y - 5) + 750 = 0 are not valid options as they are not equation that can be used to solve for y.

User Stasel
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