Question

A system of equations is given. 3y = 20 − 4x 2y = 12 − 3x Solve for (x, y) using the elimination method. please explain well

Answer 1

Answer: (-4,0)

Explanation:

3y = 20 -4x .multiply by 2

2y = 12 - 3x .multiply by 3

we get,

6y= 40 - 8x

6y= 36 - 9x

Subtracting both we get,

0 = 4 + x

x= - 4

Answer 2

(3y=20-4x)*2
(2y=12-3x)*3

6y=40-8x
6y=36-9x

Subtract

0=4-(-1x)
x=-4

Substitute in either equation

2y=12-3(-4)
2y=24
y=12

(-4,-12)