Answer:
She borrowed php4737.00.
Explanation:
This is a simple interest problem.
The simple interest formula is given by:
![E = P*I*t](https://img.qammunity.org/2022/formulas/mathematics/college/q51rka3lgfrr6eo8o4fptbwq8wwhaq8wtn.png)
In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.
After t years, the total amount of money is:
![T = E + P](https://img.qammunity.org/2022/formulas/mathematics/college/2qif3fetr4vu4r54wsug2fkorga40e4jz0.png)
6% interest:
This means that
![I = 0.06](https://img.qammunity.org/2022/formulas/mathematics/college/uskrxcnoi9ulk0bezg84ztfd1il0z8ssbz.png)
19 months:
An year has 12 months, so
![t = (19)/(12) = 1.5833](https://img.qammunity.org/2022/formulas/mathematics/college/junm0z2q9djfmlax3rqab57uiglfq91379.png)
She paid an interest of php 450. How much money did she borrow
This is P when
. So
![E = P*I*t](https://img.qammunity.org/2022/formulas/mathematics/college/q51rka3lgfrr6eo8o4fptbwq8wwhaq8wtn.png)
![450 = P*0.06*1.5833](https://img.qammunity.org/2022/formulas/mathematics/college/wlxtmwn8mw46bznl0f9pg9ya0ijl2fij6p.png)
![P = (450)/(0.06*1.5833)](https://img.qammunity.org/2022/formulas/mathematics/college/pxm1bixukfe5i3avonx4ivlytkxij6oj52.png)
![P = 4737](https://img.qammunity.org/2022/formulas/mathematics/college/qpl2ii5ki8ljofmod7rtiq61c3kd00su44.png)
She borrowed php4737.00.