Question

47.4 grams of calcium carbonate (CaCO3) is dissolved in 450 mL of water. What is the molarity of this aqueous solution?

Answer 1

`M=1.05M`

Step-by-step explanation:

Hello!

In this case, since the formula for the calculation of molarity is defined in terms of moles and volume in liters as shown below:

`M=(n)/(V)`

Whereas the moles are computed by considering the molar mass of CaCO3 (100.09 g/mol):

`n=47.4g*(1mol)/(100.09g)=0.4736mol`

Thus, we obtain:

`M=(0.4736mol)/(0.450L)\\\\M=1.05M`

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