Question

Find three consicutive integers such that twice the sum of te two is 11 more than three times the largest

Answer 1

11 & 1

Explanation:

11*1=11

11+1=12

12>11

11>1

Answer 2

Answer: Let's call the smallest of the three consecutive integers "x". Then the next two integers will be "x+1" and "x+2".

We know that the sum of the three integers is twice the largest integer plus 11. We can use this information to set up the following equation:

x + (x+1) + (x+2) = 2(x+2) + 11

Simplifying, we get:

3x + 3 = 2x + 5 + 11

So we can get:

x = 3

Therefore, the three consecutive integers are 3, 4 and 5.

Explanation: