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Although I2 is the stable form of iodine at low temperatures, at high temperatures the molecule can dissociate:

Upper I subscript 2 (g) double-headed arrow 2 upper I (g).

What is the equilibrium constant expression for this system?
K subscript e q equals StartFraction StartBracket upper I EndBracket superscript 2 over StartBracket upper I subscript 2 EndBracket EndFraction.
K subscript e q equals StartFraction StartBracket upper I EndBracket over StartBracket upper I subscript 2 EndBracket EndFraction.
K subscript e q equals StartFraction StartBracket upper I subscript 2 EndBracket over StartBracket upper I EndBracket superscript 2.

User Mykola
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2 Answers

2 votes

Answer:

Question 1 : A

Question 2: B

Question 3: In this system, the equilibrium lies to the ✔ left,and the reaction favors the reactants.

Step-by-step explanation:

Hope this helps.

Edge 2022

User Patrick Bard
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3.3k points
8 votes

Answer:

1. A

2. B

3. Left/Reactants

Step-by-step explanation:

UWU

User Jerome Dochez
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3.2k points