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1 vote
The area of a rectangle is
12x^6y^7 . If the width of the rectangle is
3x^2z , what is the length of the rectangle? A = lw

User Gage
by
6.9k points

1 Answer

3 votes

Answer:


l = (4x^4y^7)/(z)

Explanation:


A = l\cdot w

We can divide both sides of this formula by width to solve for length.


(A)/(w) = l

Then, we can plug in the given values for width and area.


(12x^6y^7)/(3x^2z) = l

Finally, we can solve for length by applying the quotient exponent rule.


(x^a)/(x^b) = x^((a-b))


(12x^6y^7)/(3x^2z) = l


4\cdot x^((6-2)) \cdot (y^7)/(z) = l


l = (4x^4y^7)/(z)

User Corno
by
6.5k points