The area of a rectangle is 12x^6y^7 . If the width of the rectangle is 3x^2z , what is the length of the rectangle? A = lw

Question

The area of a rectangle is
`12x^6y^7` . If the width of the rectangle is
`3x^2z` , what is the length of the rectangle? A = lw

Answer 1

`l = (4x^4y^7)/(z)`

Explanation:

`A = l\cdot w`

We can divide both sides of this formula by width to solve for length.

`(A)/(w) = l`

Then, we can plug in the given values for width and area.

`(12x^6y^7)/(3x^2z) = l`

Finally, we can solve for length by applying the quotient exponent rule.

`(x^a)/(x^b) = x^((a-b))`

`(12x^6y^7)/(3x^2z) = l`

`4\cdot x^((6-2)) \cdot (y^7)/(z) = l`

`l = (4x^4y^7)/(z)`