Question

Please help!! Algebra 2

Find f(2) if f(x)=5x⁵-3x⁴- 17x³-4x²+10x+21 F(2)=

Answer 1

Answer: f(2)=1

Explanation:

This is a function-related problem. In order to solve f(2), you need to substitute the value into the original function.

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f(x)=5x⁵-3x⁴- 17x³-4x²+10x+21

f(2)=5(2)⁵-3(2)⁴- 17(2)³-4(2)²+10(2)+21

f(2)=160-48-136-16+20+21

f(2)=1

Hope this helps!!

Please let me know if you have any questions

Answer 2

substitute x for 2
5(2)^5-3(2)^4-17(2)^3-4(2)^2+10(2)+21
do the exponents
5(32)-3(16)-17(8)-4(4)+10(2)+21
simplify
160-48-136-16+20+21
1
f(2)=1